document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127308>Question 127308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number, five-fourths of the number, and a third of the number is one hundred fifty-five. Find the number.\r<BR>\n" );
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document.write( "Here's what I have<BR>\n" );
document.write( "x + x + 5/4 + x + 1/3 + x =155<BR>\n" );
document.write( "4x + 5/4 + 1/3 =155<BR>\n" );
document.write( "5/4 + 1/3= 1 7/12<BR>\n" );
document.write( "4x = 1 7/12<BR>\n" );
document.write( "????? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93264 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You're on the right track, but \"five-fourths of the number\" does not translate to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B5%2F4 ALIGN=MIDDLE  ALT=\"x%2B5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. It translates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285%2F4%29x ALIGN=MIDDLE  ALT=\"%285%2F4%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" > where the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > is multiplied by x. The same applies to the statement \"third of the number \"\r<BR>\n" );
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document.write( "So our equation should look like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+%285%2F4%29x+%2B+%281%2F3%29x+=155 ALIGN=MIDDLE  ALT=\"x+%2B+%285%2F4%29x+%2B+%281%2F3%29x+=155\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2812%29%28x%2B%285%2F4%29x%2B%281%2F3%29x%29=%2812%29%28155%29 ALIGN=MIDDLE  ALT=\"%2812%29%28x%2B%285%2F4%29x%2B%281%2F3%29x%29=%2812%29%28155%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply both sides by the LCD of 12 (the LCD is the LCM of the denominators). This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a  rel=nofollow HREF=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x%2B15x%2B4x=1860 ALIGN=MIDDLE  ALT=\"12x%2B15x%2B4x=1860\"   DISABLED_style= \"max-width:90%; height:auto;\" > Distribute and multiply the LCM to each side\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=31x=1860 ALIGN=MIDDLE  ALT=\"31x=1860\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms on the left side\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%281860%29%2F%2831%29 ALIGN=MIDDLE  ALT=\"x=%281860%29%2F%2831%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 31 to isolate x\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=60 ALIGN=MIDDLE  ALT=\"x=60\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide\r<BR>\n" );
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document.write( "Answer:\r<BR>\n" );
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document.write( "So our answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=60 ALIGN=MIDDLE  ALT=\"x=60\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "So the number is 60 </SPAN>\n" );
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