document.write( "Question 127250: Janet can shovel snow from her driveway in 65 minutes. Bill can do the same job in 50 minutes. How long would it take if they worked together?\r
\n" ); document.write( "\n" ); document.write( "It would take _____ minutes.\r
\n" ); document.write( "\n" ); document.write( "I've had to do a couple of similar problems using hours, but for some reason the minutes is throwing me off. Please help!
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Algebra.Com's Answer #93229 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Janet can shovel snow from her driveway in 65 minutes. Bill can do the same job in 50 minutes. How long would it take if they worked together?
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\n" ); document.write( "Minutes, hours, days, years, it does not matter as long as you're consistent.
\n" ); document.write( "Don't use minutes for one person and hours for another, for example
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\n" ); document.write( "Let t = time to complete the job working together
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\n" ); document.write( "Let competed job = 1
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\n" ); document.write( "\"t%2F65\" + \"t%2F50\" = 1
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\n" ); document.write( "Multiply equation by a multiple of 65 and 50; 650 come to mind
\n" ); document.write( "650*\"t%2F65\" + 650*\"t%2F50\" = 650(1)
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\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "10t + 13t = 650
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\n" ); document.write( "23t = 650
\n" ); document.write( "t = \"650%2F23\"
\n" ); document.write( "t = 28.26 minutes
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\n" ); document.write( "Check solution using a calc
\n" ); document.write( "\"28.26%2F65\" + \"28.26%2F50\" = .9999 ~ 1
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