document.write( "Question 127172: Can someone please help me solve this problem?\r
\n" ); document.write( "\n" ); document.write( "3-a-4/a+3=a^2-2/a+3\r
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Algebra.Com's Answer #93228 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume it's
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\n" ); document.write( "\"3+-+%28%28a-4%29%29%2F%28%28a%2B3%29%29+=+%28%28a%5E2-2%29%29%2F%28%28a%2B3%29%29\"
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\n" ); document.write( "\"3+=+%28%28a-4%29%29%2F%28%28a%2B3%29%29+%2B+%28%28a%5E2-2%29%29%2F%28%28a%2B3%29%29\"; Added \"%28%28a-4%29%29%2F%28%28a%2B3%29%29\" to both sides
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\n" ); document.write( "They have the same denominators so we can just write it:
\n" ); document.write( "\"3+=+%28%28+a+-+4+%2B+a%5E2+-+2%29%29%2F%28%28a%2B3%29%29\" = \"3+=+%28%28a%5E2+%2B+a+-+6%29%29%2F%28%28a%2B3%29%29\"; combine like terms, we have quadratic now
\n" ); document.write( "That will factor to:
\n" ); document.write( "\"3+=+%28%28a-2%29%28a%2B3%29%29%2F%28%28a%2B3%29%29\"
\n" ); document.write( "Cancel out the (a+3)'s and we have a simple equation
\n" ); document.write( "a - 2 = 3
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\n" ); document.write( "a = 3 + 2
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\n" ); document.write( "a = 5
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\n" ); document.write( "Check solution in the original equation, substitute 5 for x
\n" ); document.write( "\"3+-+%28%285-4%29%29%2F%28%285%2B3%29%29+=+%28%285%5E2-2%29%29%2F%28%285%2B3%29%29\"
\n" ); document.write( "\"3+-+%281%29%2F%288%29+=+%28%2825-2%29%29%2F%28%288%29%29\"
\n" ); document.write( "\"3+-+%281%29%2F%288%29+=+%2823%29%2F%288%29\"
\n" ); document.write( "3 is equal to 24/8 so we have:
\n" ); document.write( "\"%2824%29%2F8+-+%281%29%2F%288%29+=+%2823%29%2F%288%29\"; confirms our solution
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\n" ); document.write( "Could you follow what we did here? Any questions?
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