document.write( "Question 127249: The answer that I have come up with is: (e -1).2:
\n" ); document.write( "The problem is what are the exact evaluation of, (integral sign), 2xe^(x^2) dx over the intervals (0, 1). I feel this is not correct, can you verify that for me please?\r
\n" ); document.write( "\n" ); document.write( "Also please, I have determined that In x is not the correct completion of the formula, (integral sign), (1/x). Is that correct, or should I do more research on this subject? \r
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Algebra.Com's Answer #93225 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"int%28+2xe%5E%28x%5E2%29%2C+dx%2C+0%2C+1+%29\" Start with the given integral\r
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\n" ); document.write( "\n" ); document.write( "Let \"u=x%5E2\". So this means that \"du=2xdx\". So the \"x%5E2\" gets replaced with \"u\" and the \"2xdx\" (you have to group these together) gets replaced with \"du\" \r
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\n" ); document.write( "\n" ); document.write( "Also, since the first endpoint is 0, this means that \"x=0\". But we want this in terms of u. So just plug in \"x=0\" into \"u=x%5E2\" to get \"u=0\". Do the same thing with the other endpoint to get \"u=1\"\r
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\n" ); document.write( "\n" ); document.write( "So we now have:\r
\n" ); document.write( "\n" ); document.write( "\"int%28+e%5Eu%2C+du%2C+0%2C+1+%29\"\r
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\n" ); document.write( "\n" ); document.write( "So we now have:\r
\n" ); document.write( "\n" ); document.write( "\"e%5Eu%2BC\" Take the integral of \"e%5Eu\" to get \"e%5Eu\". Remember \"int%28+e%5Eu%2C+du%29=e%5Eu%2BC\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's evaluate the endpoints\r
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\n" ); document.write( "\n" ); document.write( "\"%28e%5E1%2BC%29-%28e%5E0%2BC%29\" Plug in the endpoints and subtract\r
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\n" ); document.write( "\n" ); document.write( "\"e-1\" Combine like terms and simplify\r
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\n" ); document.write( "\n" ); document.write( "So \"int%28+2xe%5E%28x%5E2%29%2C+dx%2C+0%2C+1+%29=e-1\"\r
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\n" ); document.write( "\n" ); document.write( "Are you trying to evaluate \"int%28+1%2Fx%2C+dx%29\" ?\r
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\n" ); document.write( "\n" ); document.write( "The integral of \"1%2Fx\" is \"ln%28x%29%2BC\". In other words, \"int%28+1%2Fx%2C+dx%29=ln%28x%29%2BC\"
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