document.write( "Question 19285: I need help....\r
\n" ); document.write( "\n" ); document.write( "Graph the polynonmial function P(x)=x^4 + x^3 - 3x^2 -5x -2 and use the zeros (x-intercepts) to find a factorization of P(x).\r
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Algebra.Com's Answer #9320 by venugopalramana(3286)\"\" \"About 
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Graph the polynonmial function P(x)=x^4 + x^3 - 3x^2 -5x -2 and use the zeros (x-intercepts) to find a factorization of P(x).\r
\n" ); document.write( "\n" ); document.write( "give different values for x ,find P(x) and make a table as follows
\n" ); document.write( "say x=0,we get P(x)=x^4 + x^3 - 3x^2 -5x -2=0+0-0-0-2=-2
\n" ); document.write( "for x=-1,we get P(x)=(-1)^4+(-1)^3-3(-1)^2-5(-1)-2=1-1-3+5-2=0..etc..
\n" ); document.write( "x.......0.....-1.........1......etc...
\n" ); document.write( "P(x)...-2......0........-8\r
\n" ); document.write( "\n" ); document.write( "when you plot the graph it looks as follows\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+6%2C+-20%2C+80%2Cx%5E4+%2B+x%5E3+-+3x%5E2+-5x+-2+%29+\"
\n" ); document.write( "see where all the curve cuts X axis ..there Y=P(x)=0..those values of x coordinates are the roots of the polynomial.we saw P(x)=0 at x=-1..so x+1 is a factor..proced on this basis to find other factors from the graph.for ex at x=2 the curve cuts x axis and so x=2 is a root and x-2 is a factor \n" ); document.write( "
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