document.write( "Question 127225: Hello. Please help me ASAP- I need to turn this in quick. So I have a worksheet that says that I need to discriminate the solutions of the quadratic equation: x squared + 5x + 3 + a. How do I do it and what does the direction mean?\r
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Algebra.Com's Answer #93193 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! discriminate the solutions of the quadratic equation: x squared + 5x + 3 + a. \n" ); document.write( "----------------- \n" ); document.write( "The discriminant of a quadratic is b^2-4ac \n" ); document.write( "--------------- \n" ); document.write( "Your quadratic has a = 1, b=5, c=3+a \n" ); document.write( "----------- \n" ); document.write( "Your discriminant is 5^2 -4*1*(3+a) = 25-12-4a = 13-4a \n" ); document.write( "--------------------- \n" ); document.write( "When the discriminant is less than zero you have no Real Number solutions: \n" ); document.write( "13-4a < 0 \n" ); document.write( "4a>13 \n" ); document.write( "a > 13/4 \n" ); document.write( "----------- \n" ); document.write( "When the discriminant is equal to zero you have two equal Real number solutions: \n" ); document.write( "13-4a = 0 \n" ); document.write( "4a = 13 \n" ); document.write( "a = 13/4 \n" ); document.write( "------------- \n" ); document.write( "when the discriminant is greater than zero you have two unequal Real number \n" ); document.write( "solutions: \n" ); document.write( "13-4a >0 \n" ); document.write( "4a<13 \n" ); document.write( "a < 13/4 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |