document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127206>Question 127206</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321269470/algebrahomeworkh>Introductory Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I have one more problem that is stumping me.  It reads:  An open rectangular gutter is made by turning up the sides of a piece of metal 20 in. wide.  The area of the cross-section of the gutter is 50in^2.  Find the depth of the gutter.  Any help on this one would be greatly appreciated!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93173 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the sides of the rectangular gutter be D (for depth) and the length be L.<BR>\n" );
document.write( "From the description we have:<BR>\n" );
document.write( "1) 2D+L = 20 and...<BR>\n" );
document.write( "2) D*L = 50<BR>\n" );
document.write( "Rewrite equation 1) as L = 20-2D and substitute into equation 2).<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D%2820-2D%29+=+50 ALIGN=MIDDLE  ALT=\"D%2820-2D%29+=+50\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20D-2D%5E2+=+50 ALIGN=MIDDLE  ALT=\"20D-2D%5E2+=+50\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 50 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20D-2D%5E2-50+=+0 ALIGN=MIDDLE  ALT=\"20D-2D%5E2-50+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide by -2 to ease calculations.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D%5E2-10D%2B25+=+0 ALIGN=MIDDLE  ALT=\"D%5E2-10D%2B25+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve by factoring.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28D-5%29%28D-5%29+=+0 ALIGN=MIDDLE  ALT=\"%28D-5%29%28D-5%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So, D = 5<BR>\n" );
document.write( "The depth is 5 inches and the length is (20-2(5)) = 10 inches.<BR>\n" );
document.write( " </SPAN>\n" );
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