document.write( "Question 127122: Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #93156 by ankor@dixie-net.com(22740)\"\" \"About 
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Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%?
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\n" ); document.write( "Let x = amt invested at 14%
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\n" ); document.write( "It said the total invested was $20,000, therefore
\n" ); document.write( "(20000 - x) amt invested at 13%
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\n" ); document.write( ".14x + .13(20000 - x) = 2720
\n" ); document.write( ":
\n" ); document.write( ".14x + 2600 - .13x = 2720
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\n" ); document.write( ".14x - .13x = 2720 - 2600
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\n" ); document.write( ".01x = 120
\n" ); document.write( "x = \"120%2F.01\"
\n" ); document.write( "x = 12,000 invested at 14%
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\n" ); document.write( "Check solution in original equation: (amt invested at 13% = 8000)
\n" ); document.write( ".14(12000) + .13(8000) =
\n" ); document.write( "1680 + 1040 = 2720; confirms our solution \n" ); document.write( "
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