document.write( "Question 127164: The center of a circle represented by the equation (x-2)^2+(y+3)^2=100 is located in what quadrant \n" ); document.write( "

Algebra.Com's Answer #93137 by solver91311(24713) $\"\"$ $\"About$

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$\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"$ is a circle with center at (h,k) and radius r.\r
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\n" ); document.write( "\n" ); document.write( "In your example, h = 2 and k = -3, so the center is at (2,-3).\r
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\n" ); document.write( "\n" ); document.write( "The first quadrant is where x and y are both positive, and they are numbered counter-clockwise, so\r
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\n" ); document.write( "\n" ); document.write( "Q1, x > 0, y > 0
\n" ); document.write( "Q2, x < 0, y > 0
\n" ); document.write( "Q3, x < 0, y < 0
\n" ); document.write( "Q4, x > 0, y < 0.\r
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\n" ); document.write( "\n" ); document.write( "Your center is in Q4. \n" ); document.write( "

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