document.write( "Question 19275: $\"2x%5E2-3x%2B1=0\"$ Solve by completing the square. \n" ); document.write( "

Algebra.Com's Answer #9312 by Earlsdon(6294) $\"\"$ $\"About$

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Solve by completing the square:
\n" ); document.write( " $\"2x%5E2-3x%2B1=0\"$ Divide through by two to make the x^2 coefficient = 1.
\n" ); document.write( " $\"x%5E2+-+%283%2F2%29x+%2B+1%2F2+=+0\"$ Now subtract 1/2 from both sides.
\n" ); document.write( " $\"x%5E2+-+%283%2F2%29x+=+-1%2F2\"$ Complete the square in the x-terms by adding the square of half the coefficient of the x-term to both sides. That's (3/4)^2 = 9/16
\n" ); document.write( " $\"x%5E2+-+%283%2F2%29x+%2B+9%2F16+=+9%2F16+-+1%2F2\"$ Simplify and factor the left side.
\n" ); document.write( " $\"%28x+-+3%2F4%29%5E2+=+1%2F16\"$ Now take the square root of both sides.
\n" ); document.write( " $\"x+-+3%2F4+=+1%2F4\"$ and/or $\"x+-+3%2F4+=+-1%2F4\"$
\n" ); document.write( " $\"x+=+3%2F4+%2B+1%2F4\"$ and/or $\"x+=+3%2F4+-+1%2F4\"$ \r
\n" ); document.write( "\n" ); document.write( "The two roots are:\r
\n" ); document.write( "\n" ); document.write( "x = 1
\n" ); document.write( "x = 1/2 \n" ); document.write( "

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