document.write( "Question 127120: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.\r
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Algebra.Com's Answer #93119 by solver91311(24713)\"\" \"About 
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One number is x, and the other is y.\r
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\n" ); document.write( "\n" ); document.write( "x is 12 more than y: \"x=y%2B12\"\r
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\n" ); document.write( "\n" ); document.write( "The smaller number, y, plus twice the larger number, x, is 39:\r
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\n" ); document.write( "\n" ); document.write( "\"y+%2B+2x+=+39\"\r
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\n" ); document.write( "\n" ); document.write( "Substituting:
\n" ); document.write( "\"y%2B2%28y%2B12%29=39\"
\n" ); document.write( "\"3y%2B24=39\"
\n" ); document.write( "\"3y=15\"
\n" ); document.write( "\"y=5\"\r
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\n" ); document.write( "\n" ); document.write( "Since y = 5, x must be 5 + 12 = 17.\r
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\n" ); document.write( "\n" ); document.write( "Check: 5 + 2(17) = 5 + 34 = 39. Answer checks.
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