document.write( "Question 126899: Daniel and Jonathan drove separately to a park that is 12 kilometers away. Daniel left at 9:41 a.m. and arrived at 10:29 a.m. Jonathan left at 10:35 a.m. and arrived at 10:50 a.m. Jonathan drove his car at a rate that averaged 33 kph faster than Daniel. What were Daniel's and Jonathan's speeds? \n" ); document.write( "
Algebra.Com's Answer #93116 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Daniel and Jonathan drove separately to a park that is 12 kilometers away. Daniel left at 9:41 a.m. and arrived at 10:29 a.m. Jonathan left at 10:35 a.m. and arrived at 10:50 a.m. Jonathan drove his car at a rate that averaged 33 kph faster than Daniel. What were Daniel's and Jonathan's speeds?
\n" ); document.write( ":
\n" ); document.write( "Find D's travel time: 9:41 to 10:29 = 48 min = 48/60 = .8 hr
\n" ); document.write( "Find J's travel time: 10:35 to 10:50 = 15 min = 15/60 = .25 hr
\n" ); document.write( ":
\n" ); document.write( "Let s = D's rate of speed
\n" ); document.write( "Then
\n" ); document.write( "(s+33) = J's rate of speed
\n" ); document.write( ":
\n" ); document.write( "They both traveled the same distance;Write a distance equation Dist = time * speed
\n" ); document.write( ":
\n" ); document.write( "D's dist = J's dist
\n" ); document.write( ".8s = .25(s+33)
\n" ); document.write( ":
\n" ); document.write( ".8s = .25s + 8.25
\n" ); document.write( ":
\n" ); document.write( ".8s - .25s = 8.25
\n" ); document.write( ":
\n" ); document.write( ".55s = 8.25
\n" ); document.write( "s = \"8.25%2F.55\"
\n" ); document.write( "s = 15 km/hr is D's speed
\n" ); document.write( "then
\n" ); document.write( "15 + 33 = 48 km/hr is J's speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions by finding the distances (they should be the same)
\n" ); document.write( ".8 * 15 = 12 km
\n" ); document.write( ".25 * 48 = 12 \n" ); document.write( "
\n" );