document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126728>Question 126728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 2000, 70 tonnes of soil were removed from under the Leaning Tower of Pisa, and the angle the tower made with the ground was increased by about 0.5 degrees.Before that a point near the top of the tower was 50.5m from a point at the base (measured along the tower), and this top point was directly above a point on the ground 4.25m from the same base point. How much did the point on the ground move toward the base point? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93107 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the angle the tower made with the ground was increased by about 0.5 degrees.Before that a point near the top of the tower was 50.5m from a point at the base (measured along the tower), and this top point was directly above a point on the ground 4.25m from the same base point. How much did the point on the ground move toward the base point?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "I picture this as a right triangle; the hypotenuse is the tower, given as 50.5 m forms an angle with the ground. (Call it \"A\")  The base is 4.25 m to the right angle <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Use the cosine to find the angle (A) before the tower was shifted.<BR>\n" );
document.write( "Side adjacent = 4.25, Hypotenuse = 50.5 <BR>\n" );
document.write( "Cos(A) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4.25%2F50.5 ALIGN=MIDDLE  ALT=\"4.25%2F50.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A = 85.172 degrees<BR>\n" );
document.write( ":<BR>\n" );
document.write( "If .5 degrees is added to it: 85.172 + .5 = 85.672 degrees is angle A now<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the new side adjacent, call it x:<BR>\n" );
document.write( "Cos(85.672) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F50.5 ALIGN=MIDDLE  ALT=\"x%2F50.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".075466 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F50.5 ALIGN=MIDDLE  ALT=\"x%2F50.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = .075466 * 50.5<BR>\n" );
document.write( "x = 3.81 m is the side after shifting of the tower .5 degree<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the distance the point moved: 4.25 - 3.81 = .44 meter or 44 cm<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Did I make this clear? Any questions?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );