document.write( "Question 127068This question is from textbook Introductory Algebra
\n" ); document.write( ": The speed of train A is going 18 mph slower then the speed of train B. Train A travels 220 miles in the same time that it takes train B to travel 310 miles. Find the speed of each train.\r
\n" ); document.write( "\n" ); document.write( "Train A-\r
\n" ); document.write( "\n" ); document.write( "Train B- \n" ); document.write( "

Algebra.Com's Answer #93091 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Say $\"s\"$ = speed of train A
\n" ); document.write( " $\"s+%2B+18\"$ = speed of train B
\n" ); document.write( " $\"t\"$ = time each one spends
\n" ); document.write( "train A- $\"220+=+s%2At\"$
\n" ); document.write( "train B- $\"310+=+%28s+%2B+18%29%2At\"$
\n" ); document.write( "solve each one for $\"t\"$
\n" ); document.write( " $\"t+=+220%2Fs\"$
\n" ); document.write( " $\"t+=+310+%2F+%28s+%2B+18%29\"$
\n" ); document.write( " $\"220%2Fs+=+310+%2F+%28s+%2B+18%29\"$
\n" ); document.write( "multiply each side by $\"s%2A%28s+%2B+18%29\"$
\n" ); document.write( " $\"220%28s+%2B+18%29+=+310s\"$
\n" ); document.write( " $\"220s+%2B+3960+=+310s\"$
\n" ); document.write( " $\"90s+=+3960\"$
\n" ); document.write( " $\"s+=+44\"$
\n" ); document.write( " $\"s+%2B+18+=+62\"$
\n" ); document.write( "train A is going 44 mi/hr
\n" ); document.write( "train B is going 62 mi/hr
\n" ); document.write( "check:
\n" ); document.write( " $\"220%2Fs+=+310+%2F+%28s+%2B+18%29\"$
\n" ); document.write( " $\"220%2F44+=+310+%2F+%2844+%2B+18%29\"$
\n" ); document.write( " $\"5+=+5\"$
\n" ); document.write( "OK \n" ); document.write( "

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