document.write( "Question 127015: an investor is planning to invest $25,000 for one year. she plans to invest a portion of this money at 7% and the remaining at 12%. what is the maximum amount of money that can be invested at 7% in order to make at least $2,450 for the year? \n" ); document.write( "
Algebra.Com's Answer #93085 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let x be amt. invested at 7%. \n" ); document.write( ".07x+.12(25000-x)=2450 \n" ); document.write( ".07x+3000-.12x=2450 \n" ); document.write( "-.05x+3000-3000=2450-3000 \n" ); document.write( "-.05x=-550 \n" ); document.write( "-.05x/-.05=-550/-.05 \n" ); document.write( "x=$11,000. \n" ); document.write( ". \n" ); document.write( "Check: \n" ); document.write( "11000*.07=770 \n" ); document.write( "14000*.12=1680 \n" ); document.write( "770+1680=2450 \n" ); document.write( ". \n" ); document.write( "If 1 more penny were invested at 7%, that would leave 1 less penny to be invested at 12% and the total return would be less than 2450. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |