document.write( "Question 19277: \"3x%5E2-4x-5=0\" I'm supposed to use the quadratic formula to solve the following and leave the irrational roots in the simplest radical form. \n" ); document.write( "
Algebra.Com's Answer #9308 by mmm4444bot(95)\"\" \"About 
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Hello There:\r
\n" ); document.write( "\n" ); document.write( "The quadratic formula solves equations in the form of:\r
\n" ); document.write( "\n" ); document.write( "a*x^2 + b*x + c = 0 when you're given the values of a, b, and c.\r
\n" ); document.write( "\n" ); document.write( "In your equation we have a = 3, b = -4, and c = -5.\r
\n" ); document.write( "\n" ); document.write( "The quadratic formula is:\r
\n" ); document.write( "\n" ); document.write( "x = [-b +/- sqrt(b^2 - 4*a*c)]/[2*a]\r
\n" ); document.write( "\n" ); document.write( "Substitute the given values for a, b, and c.\r
\n" ); document.write( "\n" ); document.write( "x = [-(-4) +/- sqrt(4^2 - 4*3)]/[2*3]\r
\n" ); document.write( "\n" ); document.write( "x = [4 +/- sqrt(16 + 60)]/6\r
\n" ); document.write( "\n" ); document.write( "x = [4 +/- sqrt(76)]/6\r
\n" ); document.write( "\n" ); document.write( "Since 76 = 2*2*19, the square root of 76 simplifies to 2*sqrt(19)\r
\n" ); document.write( "\n" ); document.write( "x = [4 +/- 2*sqrt(19)]/6\r
\n" ); document.write( "\n" ); document.write( "There are two solutions.\r
\n" ); document.write( "\n" ); document.write( "x = 4/6 + 2*sqrt(19)/6 and x = 4/6 - 2*sqrt(19)/6\r
\n" ); document.write( "\n" ); document.write( "x = 2/3 + sqrt(19)/3\r
\n" ); document.write( "\n" ); document.write( "x = 2/3 - sqrt(19)/3\r
\n" ); document.write( "\n" ); document.write( "~ Mark
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