document.write( "Question 19278: \"2x%5E2-3x%2B1=0\"
\n" ); document.write( "Use the quadratic formula to solve the following. Leave irrational roots in the simplest radical form.
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Algebra.Com's Answer #9307 by mmm4444bot(95)\"\" \"About 
You can put this solution on YOUR website!
Hello There:\r
\n" ); document.write( "\n" ); document.write( "Do you know what the quadratic formula is? When you have a quadratic equation set equal to zero in the form:\r
\n" ); document.write( "\n" ); document.write( "a*x^2 + b*x + c = 0\r
\n" ); document.write( "\n" ); document.write( "where you're given the values of a, b, and c, then the formula allows you to find the values of x that make the equation true.\r
\n" ); document.write( "\n" ); document.write( "The quadratic formula is: x = [-b +/- sqrt(b^2-4*a*c)]/[2*a]\r
\n" ); document.write( "\n" ); document.write( "2*x^2 - 3*x + 1 = 0\r
\n" ); document.write( "\n" ); document.write( "In your problem, a = 2, b = -3, and c = 1, so just substitute these values into the formula for a, b, and c.\r
\n" ); document.write( "\n" ); document.write( "x = [-(-3) +/- sqrt([-3]^2 - 4)]/[2*(2)]\r
\n" ); document.write( "\n" ); document.write( "x = [3 +/- sqrt(9 - 8)]/4\r
\n" ); document.write( "\n" ); document.write( "x = [3 +/- sqrt(1)]/4\r
\n" ); document.write( "\n" ); document.write( "x = (3 +/- 1)/4\r
\n" ); document.write( "\n" ); document.write( "So, there are two solutions:\r
\n" ); document.write( "\n" ); document.write( "x = (3 + 1)/4 and x = (3 - 1)/4\r
\n" ); document.write( "\n" ); document.write( "x = 4/4 and x = 2/4\r
\n" ); document.write( "\n" ); document.write( "x = 1 or x = 1/2\r
\n" ); document.write( "\n" ); document.write( "~ Mark
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