document.write( "Question 127046: \r
\n" ); document.write( "\n" ); document.write( "Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of the year is $1,390, how much did she invest at 10%?\r
\n" ); document.write( "\n" ); document.write( "please help
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Algebra.Com's Answer #93062 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
.10x+.01(31,000-x)=1390
\n" ); document.write( ".10x+310-.01x=1390
\n" ); document.write( ".09x=1390-310
\n" ); document.write( ".09x=1080
\n" ); document.write( "x=1080/.09
\n" ); document.write( "x=12,000 answer for the amount invested @ 10%.
\n" ); document.write( "31,000-12,000=19,000 amount invested @ 1%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".10*12000+.01*19000=1390
\n" ); document.write( "1200+190=1390
\n" ); document.write( "1390=1390
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