document.write( "Question 126959: Mary has 84 coins that have a total value of 5.55$. if all the coins are nickels and dimes. How many of each does mary have? \n" ); document.write( "
Algebra.Com's Answer #93054 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! D+N=84 OR D=84-N \n" ); document.write( ".10D+.05N=5.55 \n" ); document.write( ".10(84-N)+.05N=555. \n" ); document.write( "8.4-.10N+.05N=5.55 \n" ); document.write( "-.05N=5.55-8.4 \n" ); document.write( "-.05N-2.85 \n" ); document.write( "N=-2.85/.05 \n" ); document.write( "N=57 IS THE NUMBER OF NICLELS. \n" ); document.write( "D+57=84 \n" ); document.write( "D=84-57 \n" ); document.write( "D=27 IS THE NUMBER OF DIMES. \n" ); document.write( "proof: \n" ); document.write( ".10*27=.05*57=5.55 \n" ); document.write( "2.70+2.85=5.55 \n" ); document.write( "5.55=5.55 \n" ); document.write( " |