document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127019>Question 127019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the length of a side of a square is increased by 3 centimeters, the perimeter of the new square is 40 centimeters more than twice the length of a side of the original square. find the dimensions of the original square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93024 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4(x+3)=2x+40<BR>\n" );
document.write( "4x+12=2x+40<BR>\n" );
document.write( "4x-2x=40-12<BR>\n" );
document.write( "2x=28<BR>\n" );
document.write( "x=28/2<BR>\n" );
document.write( "x=14 answer for the originmal length of the sides of the square.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "4(14+3)=2*14+40<BR>\n" );
document.write( "4*17=28+40<BR>\n" );
document.write( "68=68\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );