document.write( "Question 127011: how do you solve each system by substitution?
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Algebra.Com's Answer #93016 by solver91311(24713) You can put this solution on YOUR website! Find a constant value or values that you can multiply one or both equations by so that you will result in the coefficients on one of the variables having coefficients that are additive inverses. Then add the two equations together, term by term, and the result will be the elimination of one of the variables.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Example:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You could multiply the first equation by -1 to get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or, you could multiply the first equation by 3 and the second equation by -2, giving you:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Adding gives you \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |