document.write( "Question 127004: find three consecutive integers such that 3 times the sqaure of the first exceeds the product of the other two by 25 \n" ); document.write( "
Algebra.Com's Answer #93014 by solver91311(24713)\"\" \"About 
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First integer: x
\n" ); document.write( "Second integer: x + 1
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\n" ); document.write( "\n" ); document.write( "3 times the square of the first: \"3x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "The product of the other two: \"%28x%2B1%29%28x%2B2%29=x%5E2%2B3x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "3 times the square of the first exceeds the product of the other two by 25:\"3x%5E2=%28x%5E2%2B3x%2B2%29%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-x%5E2-3x-27=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-3x-27\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282x-9%29%28x%2B3%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x=9%2F2\" or \"x=-3\". We can exclude the first root because it is not an integer. So the first integer is -3, the second would be -2, and the third, -1.\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"3%28-3%29%5E2=27\"
\n" ); document.write( "\"%28-1%29%28-2%29%2B25=27\", answer checks
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