document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95>Question 95</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the  sum  of two numbers  in  9. the  difference  between  five  times  of  the  first  and  four  times  of  the  second  is 9. what  are  that  numbers?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93 by </B><A HREF=/tutors/aboutme.mpl?userid=terrtwo><B>terrtwo(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=terrtwo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> translates Algebraically into:\r<BR>\n" );
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document.write( "x + y = 9 AND 5x - 4y = 9.\r<BR>\n" );
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document.write( "Solving the first eqaution for y, y = 9 - x.\r<BR>\n" );
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document.write( "Then substituting the first equation into the second:\r<BR>\n" );
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document.write( " 5x - 4(9 - x) = 9 --> 5x - 36 + 4x = 9 --> 9x - 36 = 9.\r<BR>\n" );
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document.write( "Adding 36 to both sides --> 9x -36 + 36 = 9 + 36 --> 9x = 45.\r<BR>\n" );
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document.write( "Divide both sides by 9 --> 9x/9 = 45/9 --> x = 5.\r<BR>\n" );
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document.write( "Not finished yet since we still must go back to find y by subsititing the known value of x into either of the orginal equations --> 5 + y = 9\r<BR>\n" );
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document.write( "Substact 5 from both sides --> 5 + y - 5 = 9 - 5 --> y = 4\r<BR>\n" );
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document.write( "Therefore x = 5, y = 4 </SPAN>\n" );
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