document.write( "Question 126975: Hi I keep doing something wrong in this problem. Can you help me solve it? thanks\r
\n" ); document.write( "\n" ); document.write( "A function is given below. Determine the average rate of change of the function between x = -4 and x = 1.\r
\n" ); document.write( "\n" ); document.write( "h(t) = t^2 - 10t
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Algebra.Com's Answer #92996 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
The average rate of change of f(x) between x = a and x = b is given by the slope of the line that passes through the points (a, f(a)) and (b, f(b)) (called a secant line). Given two points, you can calculate a slope using the formula:\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B1%5D-y%5B2%5D%29%2F%28x%5B1%5D-x%5B2%5D%29\", so for the slope of the described secant line:\r
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\n" ); document.write( "\n" ); document.write( "\"%28f%28a%29-f%28b%29%29%2F%28a-b%29\"\r
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\n" ); document.write( "\n" ); document.write( "For your function:\r
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\n" ); document.write( "\n" ); document.write( "\"a+=+-4\", so \"f%28a%29=f%28-4%29=%28-4%29%5E2-10%28-4%29=16%2B40=56\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=+1\", so \"f%28b%29=f%281%29=%281%29%5E2-10%281%29=1-10=-9\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28f%28a%29-f%28b%29%29%2F%28a-b%29=%2856-%28-9%29%29%2F%28-4-1%29=65%2F-5=-13\"\r
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\n" ); document.write( "\n" ); document.write( "Let's draw a picture and see if the answer makes sense:\r
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\n" ); document.write( "\n" ); document.write( "The secant line pictured doesn't look as steep as it should be for a -13 slope, but that is because I have different scales for the x and y axis so that you can actually see something. But the intersection points look correct and the configuration of the parabola is right (vertex at (5,-25), zeros at 0 and 10, concave up, etc.)
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