document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126979>Question 126979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3in. less than twice its width. If the perimeter of the rectangle is 145 in.  find the dimension of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92995 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W-3<BR>\n" );
document.write( "2W+2(2W-3)=145<BR>\n" );
document.write( "2W+4W-6=145<BR>\n" );
document.write( "6W=145+6<BR>\n" );
document.write( "6W=151<BR>\n" );
document.write( "W=151/6<BR>\n" );
document.write( "W=25.167 IN. IS THE WIDTH.<BR>\n" );
document.write( "2*25.167-3=47.33 IN. IS THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*25.167+2*47.33=145<BR>\n" );
document.write( "50.33+94.67=145<BR>\n" );
document.write( "145=145\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );