document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19228>Question 19228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve:\r<BR>\n" );
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document.write( "5x+3y-2z=112<BR>\n" );
document.write( "7x+5y=70<BR>\n" );
document.write( "3x+y=9z+96\r<BR>\n" );
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document.write( "and\r<BR>\n" );
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document.write( "3w+3x+6y+5z=10<BR>\n" );
document.write( "4w+5x+8y+2z=15<BR>\n" );
document.write( "3w+6x+7y+4z=30<BR>\n" );
document.write( "4w+x+6y+3z=25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9299 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first one...find x in terms of y from the second equation, then sub this into equations 1 and 3 to end up with 2 other equations in just y and z. Then solve these 2 as normal.\r<BR>\n" );
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document.write( "As for the 4 equations in 4 unknowns...honestly, i would cry if i was you. You need Gaussian Elimination or Cramer's rule (if you can do 4x4 determinants!). Good luck!  Look into the Lessons on this website, there are a few there that should help you.\r<BR>\n" );
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document.write( "Jon </SPAN>\n" );
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