document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126904>Question 126904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A STUDENT WITH A 1.875 GPA HAS 24 CREDIT HOURS.  FIND HOW MANY CREDIT HOURS OF B's (AT 3 POINTS PER CREDIT HOUR) HE WILL NEED TO RAISE HIS GPA TO A 2.40. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92955 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A STUDENT WITH A 1.875 GPA HAS 24 CREDIT HOURS.  FIND HOW MANY CREDIT HOURS OF B's (AT 3 POINTS PER CREDIT HOUR) HE WILL NEED TO RAISE HIS GPA TO A 2.40.<BR>\n" );
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document.write( "Let \"x\" be the number of B-credit hours he needs.<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "(24*1.875+3x)/(24+x)=2.40<BR>\n" );
document.write( "(45+3x)=57.6+2.4x<BR>\n" );
document.write( "12.6 = 0.6x<BR>\n" );
document.write( "x = 21<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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