document.write( "Question 126875: How many pounds of a 12% aluminum alloy must be mixed with 400 pounds of a 25% aluminum alloy to make a 17% aluminum alloy? \n" ); document.write( "
Algebra.Com's Answer #92945 by josmiceli(19441)\"\" \"About 
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In words:
\n" ); document.write( "(pounds of aluminum in 12% alloy) + (pounds of aluminum in 25% alloy)
\n" ); document.write( "divided by (total pounds of mixture) = 17%
\n" ); document.write( "Let \"a\" = pounds of 12% alloy needed
\n" ); document.write( "Let \"b\" = pounds of 25% alloy needed
\n" ); document.write( "\"%28.12a+%2B+.25b%29+%2F+%28a+%2B+b%29+=+.17\"
\n" ); document.write( "\"b+=+400\"
\n" ); document.write( "\"%28.12a+%2B+.25%2A400%29+%2F+%28a+%2B+400%29+=+.17\"
\n" ); document.write( "\"%28.12a+%2B+100%29+%2F+%28a+%2B+400%29+=+.17\"
\n" ); document.write( "\".12a+%2B+100+=+.17%28a+%2B+400%29\"
\n" ); document.write( "\".12a+%2B+100+=+.17a+%2B+68\"
\n" ); document.write( "\".05a+=+32\"
\n" ); document.write( "\"a+=+640\"
\n" ); document.write( "640 pounds of 12% alloy must be used
\n" ); document.write( "check answer
\n" ); document.write( "\"%28.12a+%2B+.25b%29+%2F+%28a+%2B+b%29+=+.17\"
\n" ); document.write( "\"%28.12%2A640+%2B+.25%2A400%29+%2F+1040+=+.17\"
\n" ); document.write( "\"%2876.8+%2B+100%29+%2F+1040+=+.17\"
\n" ); document.write( "\"176.8+=+1040%2A.17\"
\n" ); document.write( "\"176.8+=+176.8\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );