document.write( "Question 126858This question is from textbook Intermediate Algebra
\n" ); document.write( ": A collection of nickels, dimes, and quarters amounts to $10.00. If there are 140 coins in all and there are twice as many dimes as there are quarters, find the number of nickels. \n" ); document.write( "
Algebra.Com's Answer #92938 by edjones(8007)\"\" \"About 
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Let n=number of nickels, d=dimes, q=quarters
\n" ); document.write( "A) n+d+q=140
\n" ); document.write( "B) .05n+.1d+.25q=10
\n" ); document.write( "C) d=2q
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\n" ); document.write( "A)
\n" ); document.write( "n+2q+q=140
\n" ); document.write( "n+3q=140
\n" ); document.write( "n=140-3q
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\n" ); document.write( "B)
\n" ); document.write( ".05(140-3q)+.1(2q)+.25q=10
\n" ); document.write( "7-.15q+.2q+.25q=10
\n" ); document.write( "7+.3q=10
\n" ); document.write( ".3q=3
\n" ); document.write( "q=3/.3
\n" ); document.write( "q=10
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\n" ); document.write( "C)
\n" ); document.write( "d=2*10
\n" ); document.write( "d=20
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\n" ); document.write( "A)
\n" ); document.write( "n+20+10=140
\n" ); document.write( "n+30=140
\n" ); document.write( "n=110 Ans.
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\n" ); document.write( "Check:
\n" ); document.write( "B)
\n" ); document.write( ".05*110+.1*20+.25*10=10
\n" ); document.write( "5.5+2+2.5=10 True
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\n" ); document.write( "Ed
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