document.write( "Question 126858This question is from textbook Intermediate Algebra
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document.write( ": A collection of nickels, dimes, and quarters amounts to $10.00. If there are 140 coins in all and there are twice as many dimes as there are quarters, find the number of nickels. \n" );
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Algebra.Com's Answer #92938 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let n=number of nickels, d=dimes, q=quarters \n" ); document.write( "A) n+d+q=140 \n" ); document.write( "B) .05n+.1d+.25q=10 \n" ); document.write( "C) d=2q \n" ); document.write( ". \n" ); document.write( "A) \n" ); document.write( "n+2q+q=140 \n" ); document.write( "n+3q=140 \n" ); document.write( "n=140-3q \n" ); document.write( ". \n" ); document.write( "B) \n" ); document.write( ".05(140-3q)+.1(2q)+.25q=10 \n" ); document.write( "7-.15q+.2q+.25q=10 \n" ); document.write( "7+.3q=10 \n" ); document.write( ".3q=3 \n" ); document.write( "q=3/.3 \n" ); document.write( "q=10 \n" ); document.write( ". \n" ); document.write( "C) \n" ); document.write( "d=2*10 \n" ); document.write( "d=20 \n" ); document.write( ". \n" ); document.write( "A) \n" ); document.write( "n+20+10=140 \n" ); document.write( "n+30=140 \n" ); document.write( "n=110 Ans. \n" ); document.write( ". \n" ); document.write( "Check: \n" ); document.write( "B) \n" ); document.write( ".05*110+.1*20+.25*10=10 \n" ); document.write( "5.5+2+2.5=10 True \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |