document.write( "Question 126841This question is from textbook texas algebra 1
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document.write( ": Use a system of linear equations to solve the problem.\r
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document.write( "On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the return trip downstream (with the current), her averagespeed was 3 mi/h. Find Rita's paddling speed in still water and the speed of the river's current. \n" );
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Algebra.Com's Answer #92921 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the return trip downstream (with the current), her average speed was 3 mi/h. Find Rita's paddling speed in still water and the speed of the river's current. \n" ); document.write( ": \n" ); document.write( "Let x = speed in still water \n" ); document.write( "Let y = speed of the current \n" ); document.write( ": \n" ); document.write( "Two equations, one downstream and one downstream \n" ); document.write( "x + y = 3 \n" ); document.write( "x - y = 2 \n" ); document.write( "-----------adding eliminates y \n" ); document.write( "2x +0 = 5 \n" ); document.write( "x = \n" ); document.write( "x = 2.5 mph in still water \n" ); document.write( ": \n" ); document.write( "Find y using x + y = 3; Substitute 2.5 for x \n" ); document.write( "2.5 + y = 3 \n" ); document.write( "y = 3 - 2.5 \n" ); document.write( "y = .5 mph is the current \n" ); document.write( ": \n" ); document.write( "Check solution in the upstream equation \n" ); document.write( "2.5 - .5 = 2 \n" ); document.write( " |