document.write( "Question 126841This question is from textbook texas algebra 1
\n" ); document.write( ": Use a system of linear equations to solve the problem.\r
\n" ); document.write( "\n" ); document.write( "On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the return trip downstream (with the current), her averagespeed was 3 mi/h. Find Rita's paddling speed in still water and the speed of the river's current.
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Algebra.Com's Answer #92921 by ankor@dixie-net.com(22740)\"\" \"About 
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On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the return trip downstream (with the current), her average speed was 3 mi/h. Find Rita's paddling speed in still water and the speed of the river's current.
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\n" ); document.write( "Let x = speed in still water
\n" ); document.write( "Let y = speed of the current
\n" ); document.write( ":
\n" ); document.write( "Two equations, one downstream and one downstream
\n" ); document.write( "x + y = 3
\n" ); document.write( "x - y = 2
\n" ); document.write( "-----------adding eliminates y
\n" ); document.write( "2x +0 = 5
\n" ); document.write( "x = \"5%2F2\"
\n" ); document.write( "x = 2.5 mph in still water
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\n" ); document.write( "Find y using x + y = 3; Substitute 2.5 for x
\n" ); document.write( "2.5 + y = 3
\n" ); document.write( "y = 3 - 2.5
\n" ); document.write( "y = .5 mph is the current
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\n" ); document.write( "Check solution in the upstream equation
\n" ); document.write( "2.5 - .5 = 2
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