document.write( "Question 126848: \"x%5E2%2Fx-2=4%2Fx-2\" I don't know if I typed this question out right. It should be x squared over x-2 = 4 over x-2. And the instructions are to solve for x.
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\n" ); document.write( "shelena
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Algebra.Com's Answer #92912 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"x%5E2%2F%28x-2%29=4%2F%28x-2%29\" ....if denominators are same, then nominators must be too if we have equal sign, so you have:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=4\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%284%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x1=2\"\r
\n" ); document.write( "\n" ); document.write( "\"x2=-2\"
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