document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126807>Question 126807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two opposite sides of a square are increased by 6 meters and the other sides are decreases by 4 meters, the area of the rectangle that is formed is 96 square meters. Find the area of the original square.\r<BR>\n" );
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document.write( "I've gotten as far as finding x at least I think 10, -12...but I don't know where to go from there. :( </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92910 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+6)(x-4)=96<BR>\n" );
document.write( "x^2+6x-4x-24=96<BR>\n" );
document.write( "x^2+2x-24-96=0<BR>\n" );
document.write( "x^2+2x-120=0<BR>\n" );
document.write( "(x+12)(x-10)=0<BR>\n" );
document.write( "x-10=0<BR>\n" );
document.write( "x=10 meters is the length of the square sides.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(10+6)(10-4)=96<BR>\n" );
document.write( "16*6=96<BR>\n" );
document.write( "96=96<BR>\n" );
document.write( " </SPAN>\n" );
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