document.write( "Question 126836This question is from textbook
\n" ); document.write( ": Leo held a garage sale. He priced all the items at a dime or a quarter. His sales totaled less than $5.
\n" ); document.write( "Write a linear inequality for this situation
\n" ); document.write( "What is the maximum possible number of items that could have been sold for a dime?
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Algebra.Com's Answer #92908 by solver91311(24713)\"\" \"About 
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$5.00 is 500 cents, 10d is the amount in cents received from selling d items for a dime, and 25q is the amount in cents received from selling q items for a quarter.\r
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\n" ); document.write( "\n" ); document.write( "\"10d+%2B+25q+%3C+500\"\r
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\n" ); document.write( "\n" ); document.write( "This could also be expressed as \"0.10d+%2B+0.25q=5.00\", but I happen to think decimal coefficients are messy and best avoided if possible. Then again, maybe I'm related to Monk.\r
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\n" ); document.write( "\n" ); document.write( "The maximum number of items that could have been sold for a dime is when zero items sold for a quarter, so the inequality reduces to:\r
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\n" ); document.write( "\n" ); document.write( "\"10d+%3C+500\"\r
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\n" ); document.write( "\n" ); document.write( "Dividing by 10:
\n" ); document.write( "\"d+%3C+50\"\r
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\n" ); document.write( "\n" ); document.write( "Since fractional parts of a dime are not allowed in this situation, the most items that could have been sold for a dime was 49, one less than 50.
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