document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19109>Question 19109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The formula for the perimeter of a rectangle is P=2L+2W where L is the length and W is the width. A rectangle has a perimeter of 24 inches. Find its dimensions if it's length is 3 inches greater than it's width. I kinda know what I'm doing but I need some help like explaining how to egt the answer with the work. But I'm not completely lost! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9290 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let width = x  because it is unknown.<BR>\n" );
document.write( "Let length = x + 3\" because it is 3\" greater.\r<BR>\n" );
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document.write( "P = 2L + 2W<BR>\n" );
document.write( "24\" = 2(x+3\") + 2(x)<BR>\n" );
document.write( "24\" = 2x + 6\" + 2x<BR>\n" );
document.write( "24\" - 6\" = 4x<BR>\n" );
document.write( "18\" = 4x<BR>\n" );
document.write( "18\"/4 = x<BR>\n" );
document.write( "4.5\" = x\r<BR>\n" );
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document.write( "To check the answer go back and substitute 4.5\" for x in the equation and see if you get a perimeter of 24\". </SPAN>\n" );
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