document.write( "Question 126824: How do you solve the exponential equation -5e^-x+9=6 \n" ); document.write( "
Algebra.Com's Answer #92899 by solver91311(24713)\"\" \"About 
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\"-5e%5E%28-x%29%2B9=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"-5e%5E%28-x%29=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%28-x%29=%28-3%29%2F-5\"\r
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\n" ); document.write( "\n" ); document.write( "Now take the natural logarithm of both sides
\n" ); document.write( "\"log%28e%2Ce%5E%28-x%29%29=log%28e%2C3%2F5%29\"\r
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\n" ); document.write( "\n" ); document.write( "Apply \"log%28b%2Cx%5Em%29=m%2Alog%28b%2Cx%29\" and \"log%28b%2Ca%2Fc%29=log%28b%2Ca%29-log%28b%2Cc%29\"
\n" ); document.write( "\"-x%2Alog%28e%2Ce%29=log%28e%2C3%29-log%28e%2C5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28e%2Ce%29=1\" so:
\n" ); document.write( "\"-x=log%28e%2C3%29-log%28e%2C5%29\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, multiply by -1
\n" ); document.write( "\"x=log%28e%2C5%29-log%28e%2C3%29\"
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