document.write( "Question 126801: 1. Use the logarithm properties to present the expression log(x + 10) - log x as the logarithm of a single quantity.\r
\n" ); document.write( "\n" ); document.write( "2.Fill in the blank to make a true statement. To solve 3 x = 26, we can take the logarithm of each side of the equation to get log (3 x ) = log (26). The power rule for logarithms would then provide a way of moving the variable x from its position as an __________ to the position of a coefficient. \r
\n" ); document.write( "\n" ); document.write( "3.Write the equation in logarithmic form (1/5)^-7=78125\r
\n" ); document.write( "\n" ); document.write( "4.Find the value of x: log3 9 = x
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #92889 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
1. The log rule you need to apply is \"log%28b%2Ca%29-log%28b%2Cc%29=log%28b%2Ca%2Fc%29\". So,\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%2B10%29-log%28x%29=log%28%28x%2B10%29%2Fx%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2. I'm presuming you meant to say \"3%5Ex=26\". The missing word is then 'exponent'\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3. \"%281%2F5%29%5E-7=78125\"\r
\n" ); document.write( "\n" ); document.write( "This can be re-written as \"5%5E7=78125\". We know that if \"log%28b%2Cx%29=y\" then \"b%5Ey=x\", so \"5%5E7=78125\" implies \"log%285%2C78125%29=7\". Of course, you could also have left the equation in its original state and said \"log%28%281%2F5%29%2C78125%29=-7\", but that is very messy. Monk wouldn't approve.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "4. \"log%283%2C9%29=x\" => \"3%5Ex=9\". But we know that \"9=3%5E2\" so we can write \"3%5Ex=3%5E2\". Since we also know that \"b%5Em=b%5En\" if and only if \"m=n\", \"x=2\".
\n" ); document.write( "
\n" );