document.write( "Question 126685: A beeswax candle is made by repeatedly dipping the wick into the molten wax. Paraffin candles are usually made by pouring the molten wax into forms with wick shafts, and the wick is added as the last step. One type of beeswax candle burns up in 6 hours. Another paraffin candle of the same length burns up in 9 hours. If both candles are lit at the same time, how much time will pass before one is twice as long as the other? \n" ); document.write( "
Algebra.Com's Answer #92886 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! One type of beeswax candle burns up in 6 hours. Another paraffin candle of the same length burns up in 9 hours. If both candles are lit at the same time, how much time will pass before one is twice as long as the other? \n" ); document.write( ": \n" ); document.write( "Choose a convenient length; 18\" is a good length (has a lot of factors) \n" ); document.write( ": \n" ); document.write( "The b candle burns at a rate of 18/6 = 3\" per/hr \n" ); document.write( "The p candle burns at a rate of 18/9 = 2\" per/hr \n" ); document.write( ": \n" ); document.write( "Let t = time (in hrs) elapsed for p to be twice as long as b \n" ); document.write( ": \n" ); document.write( "18 - 2t = 2(18 - 3t) \n" ); document.write( ": \n" ); document.write( "18 - 2t = 36 - 6t \n" ); document.write( ": \n" ); document.write( "-2t + 6t = 36 - 18 \n" ); document.write( ": \n" ); document.write( "4t = 18 \n" ); document.write( "t = \n" ); document.write( "t = 4.5 hrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( "18 - 4.5(2) = 9\" \n" ); document.write( "18 - 4.5(3) = 4.5\" \n" ); document.write( " |