document.write( "Question 126736: The sum of two numbers is 17 and the sum of their square is 145. Find the larger number.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #92866 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
If one number is x and the other y, their sum, x + y is 17. The sum of their squares, \"x%5E2%2By%5E2=145\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since \"x%2By=17\", \"y+=+17-x\", so\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2=145\"
\n" ); document.write( "\"x%5E2%2B%2817-x%29%5E2=145\"
\n" ); document.write( "\"x%5E2%2B%28289-34x%2Bx%5E2%29=145\"
\n" ); document.write( "\"2x%5E2-34x%2B289-145=0\"
\n" ); document.write( "\"2x%5E2-34x%2B144=0\"
\n" ); document.write( "\"x%5E2-17x%2B72=0\"\r
\n" ); document.write( "\n" ); document.write( "\"-8%2A-9=72\" and \"-8%2B%28-9%29=+-17\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-8%29%28x-9%29+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So, x is either 8 or 9, and then y is either 9 or 8. Either way, the larger number is 9.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check: \"8%2B9=17\" and \"8%5E2%2B9%5E2=64%2B81=145\"
\n" ); document.write( "
\n" );