document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126725>Question 126725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ONE ANGLE OF A TRIANGLE HAS A MEASURE THAT IS 10 MORE THAN TWICE THAT OF THE SECOND ANGLE.  THE THIRD ANGLE HAS A MEASURE 10 LESS THAN THE FIRST.  FIND THE MEASURE OF EACH ANGLE OF THE TRIANGLE.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92863 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+10, x, (2x+10-10) are the three angles.<BR>\n" );
document.write( "2x+10+x+2x+10-10=180<BR>\n" );
document.write( "5x=180-10<BR>\n" );
document.write( "5x=170<BR>\n" );
document.write( "x=170/5<BR>\n" );
document.write( "x=34 degrees for the second angle.<BR>\n" );
document.write( "2*34+10=68+10=78 degrees for the first angle.<BR>\n" );
document.write( "2*34+10-10=68 degrees for the third angle.<BR>\n" );
document.write( "PROOF: <BR>\n" );
document.write( "34+78+68=180<BR>\n" );
document.write( "180=180\r<BR>\n" );
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document.write( " </SPAN>\n" );
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