document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126737>Question 126737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 15 feet less than its length, and the perimeter is 210 feet.  Find the width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92858 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L-15<BR>\n" );
document.write( "2L+2W=210<BR>\n" );
document.write( "2L+2(L-15)=210<BR>\n" );
document.write( "2L+2L-30=120<BR>\n" );
document.write( "4L=210+30<BR>\n" );
document.write( "4L=240<BR>\n" );
document.write( "4L=240/4<BR>\n" );
document.write( "L=60 FOR THE LENGTH.<BR>\n" );
document.write( "W=60-15<BR>\n" );
document.write( "W=45 FOR THE LENGTH.<BR>\n" );
document.write( "PROOF: 2*60+2*45=210<BR>\n" );
document.write( "120+90=210<BR>\n" );
document.write( "210=210<BR>\n" );
document.write( " </SPAN>\n" );
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