document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126714>Question 126714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the resistance(R) of a wire is directly proportionnal to the lenght(L) and inversely proportional to the diameter(D) since a wire to 3 metres long with a diameter of o,25 centimetre has a resistance of 12 OHMS, calulate the length of a wire diameter of 0,3 centimetres and a resistance of 20 OHMS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92844 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the resistance(R) of a wire is directly proportionnal to the lenght(L) and inversely proportional to the diameter(D) since a wire to 3 metres long with a diameter of o,25 centimetre has a resistance of 12 OHMS, calulate the length of a wire diameter of 0,3 centimetres and a resistance of 20 OHMS<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "R = k*L/D<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Find k:<BR>\n" );
document.write( "12 = k*3/0.25<BR>\n" );
document.write( "3 = 3k<BR>\n" );
document.write( "k = 1<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "R = L/D<BR>\n" );
document.write( "20 = L/0.3<BR>\n" );
document.write( "L = 6 meters<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );