document.write( "Question 126638: Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 year? After 2 years? \n" ); document.write( "
Algebra.Com's Answer #92828 by checkley71(8403) ![]() You can put this solution on YOUR website! Pe^(RT) \n" ); document.write( "2000*2.718^(.06*1) \n" ); document.write( "2000*2.718^.06 \n" ); document.write( "2000*1.062=$2,123 AMOUNT OF THE INVESTMENT AFTER 1 YEAR. \n" ); document.write( "-------------------------------- \n" ); document.write( "2000*2.718^(.06*2) \n" ); document.write( "2000*2.718^.12 \n" ); document.write( "2000*1.127=$2,254.97 AMOUNT OF THE INVESTMENT AFTER 2 YEARS. \n" ); document.write( " |