document.write( "Question 126658This question is from textbook Elementary Statistics
\n" ); document.write( ": In a survey of 1002 people, 701 said that they voted in a recent presidental election (based on data from ICR Research Group). Voting records show that 61% of eligible voters actually did vote.\r
\n" ); document.write( "\n" ); document.write( "a. Find a 99% confidence interval estimate of the proportion of people who say that they voted.\r
\n" ); document.write( "\n" ); document.write( "b. Are the results consistent with the actual voter turnout of 61% why or why not?
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Algebra.Com's Answer #92825 by stanbon(75887)\"\" \"About 
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In a survey of 1002 people, 701 said that they voted in a recent presidental election (based on data from ICR Research Group). Voting records show that 61% of eligible voters actually did vote.
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\n" ); document.write( "a. Find a 99% confidence interval estimate of the proportion of people who say that they voted.\r
\n" ); document.write( "\n" ); document.write( "p-hat = x/n = 701/1002 = 0.6996
\n" ); document.write( "E=z*sqrt[(p-hat)(q-hat)/n]
\n" ); document.write( "= 2.575*sqrt[(0.6996)(0.3004)/1002] = 0.037292
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\n" ); document.write( "99% C.I.: (0.6996-0.03729,0.6996+0.0729)
\n" ); document.write( "= (0.662308,0.736892)\r
\n" ); document.write( "\n" ); document.write( "b. Are the results consistent with the actual voter turnout of 61% why or why not?
\n" ); document.write( "No, because 61% does not fall in the confidence interval
\n" ); document.write( "range of values for p.\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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