document.write( "Question 126660: **Sorry if this appears twice, it doesn't seem to have worked the first time.\r
\n" ); document.write( "\n" ); document.write( "A hyperbola with the transverse axis on the line y=-5, length of transverse axis = 6, conjugate axis on the line x = 2, and length of conjugate axis = 6. \r
\n" ); document.write( "\n" ); document.write( "I need to use this information and put this hyperbola into an equation in the Ax2+By^2+cxy+Dx+Ey+F=0\r
\n" ); document.write( "\n" ); document.write( "So far, I know that the center is at (2,-5) and both a and b = 3. (at least I think)\r
\n" ); document.write( "\n" ); document.write( "I am really having problems putting it into the form that they ask. Help would be greatly appreciated!!
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Algebra.Com's Answer #92811 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
So far, so good.\r
\n" ); document.write( "\n" ); document.write( "The center is at (2,-5) because that is where the transverse and conjugate axes intersect, and both a and b = 3 because a is the length of the transverse axis divided by 2 and b is the length of the conjugate axis divided by 2.\r
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\n" ); document.write( "\n" ); document.write( "Since the transverse axis is horizontal, this is an 'east-west' opening hyperbola. The formula for such a hyperbola centered at (h,k) is:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "Substituting the coordinates of the center and the a and b values we get:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2%2F3%5E2-%28y-%28-5%29%29%5E2%2F3%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2%2F9-%28y%2B5%29%5E2%2F9=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2-%28y%2B5%29%5E2=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x%2B4-%28y%5E2%2B10y%2B25%29=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x%2B4-%28y%5E2%2B10y%2B25%29=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-y%5E2-4x-10y%2B4-25-9=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-y%5E2-4x-10y-30=0\"\r
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\n" ); document.write( "\n" ); document.write( "The correct form is actually:\r
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\n" ); document.write( "\n" ); document.write( "\"Ax%5E2+%2B+Bxy+%2B+Cy%5E2+%2B+Dx+%2B+Ey+%2B+F+=+0\", but it doesn't matter in this case because the coefficient on the xy term is 0. You only get a non-zero coefficient on the xy term if the transverse and conjugate axes are other than parallel to the coordinate axes.
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