document.write( "Question 126673: Find three consecutive odd integers whose sum is three times the third integer \n" ); document.write( "
Algebra.Com's Answer #92801 by solver91311(24713)\"\" \"About 
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If the first odd integer is x, the second one would be x + 2, and the third one would be x + 4.\r
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\n" ); document.write( "\n" ); document.write( "The sum of the three is \"x+%2B+%28x+%2B+2%29+%2B+%28x+%2B+4%29\" but this is equal to 3 times the third odd integer \"3%28x%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+%2B+%28x+%2B+2%29+%2B+%28x+%2B+4%29=3%28x%2B4%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B6=3x%2B12\"\r
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\n" ); document.write( "\n" ); document.write( "Adding -3x to both sides of the equation leads to the absurdity that \"6=12\". Therefore, there is no solution to the problem as stated.\r
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\n" ); document.write( "\n" ); document.write( "Had the problem said 3 times the SECOND integer we would have achieved the result that \"6=6\" -- true no matter what x is. Meaning that any three consecutive odd integers would exhibit the property that their sum is equal to 3 times the second integer. In fact, any three consecutive EVEN integers, or just any three consecutive integers also exhibit the same property.
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