document.write( "Question 126664: I have a 2 questions, they are comfusing me, Laura and Brent paddled a canoe 6 miles upstream in four hours. The return trip took 3 hours. Find the rate at which Laura and Brent paddled the canoe in still water......that is one, and the other is, The sum of the digits of a 2-digit # is 11. If the digits are reversed, the new number is 45 more than the original numer. Find the number \n" ); document.write( "
Algebra.Com's Answer #92795 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! You know that distance = rate X time or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For both the upstream and downstream trips we know the distance is 6 miles and the times, 4 hours and 3 hours respectively.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the upstream trip, the true rate of speed of the boat is the boat's rate of speed in still water MINUS the rate of the current. For the downstream trip, the true rate is the still water rate PLUS the rate of the current.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Upstream equation: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Downstream equation: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now add the equations, term-by-term: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And solve: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the rate in still water is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "To go 6 miles in 4 hours, the true rate must have been \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "================================================================\r \n" ); document.write( "\n" ); document.write( "Let the 10s digit be x and the 1s digit be y. The sum of the digits is 11, so:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And the original number is n, where \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you reverse the digits, the new number which is 45 more than the old number would be given by:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we have two expressions that are equal to n, so we can set these two expressions equal to each other:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From our first equation: \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now substituting this value for x into the first equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the original number is 38.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( "\n" ); document.write( "3 + 8 = 11.\r \n" ); document.write( "\n" ); document.write( "83 - 38 = 45. Answer checks. \n" ); document.write( " |