document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126621>Question 126621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 60 mililiter soulution has 50% acid. How much pure water is needed to get 25% acid. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92790 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60*.5=30 liters of acid<BR>\n" );
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document.write( "Let x be the amount of water required to make a 25% solution with 30 liters of acid<BR>\n" );
document.write( "x *.25=30<BR>\n" );
document.write( "x=30/.25<BR>\n" );
document.write( "x=120 ml of .25% acid<BR>\n" );
document.write( "120-60=60 ml of water required.<BR>\n" );
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document.write( "Ed<BR>\n" );
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