document.write( "Question 126609: the length of a rectangle is 7 feet more than width. if the length were decreased by 3 feet and the width were increased by 2 feet, the perimeter would be 32 feet. Find the length of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #92772 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! The length of the original rectangle is L, and the width is W. We also know that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we decrease the length by 3 we get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is given by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now collect terms and solve: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since W is 5, L must be 5 + 7 = 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "If we decrese the length by 3, we get 9, and if we increase the width by 2 we get 7. (2 * 9) + (2 * 7) = 18 + 14 = 32. Answer checks. \n" ); document.write( " |