document.write( "Question 126591This question is from textbook College Algebra
\n" ); document.write( ": The volume V of a given mass of gas varies directly as the temperature T and inversely as the 19)
\n" ); document.write( "pressure P. If V = 465.0 in.3 when T = 310° and P = 10 lb/in.2, what is the volume when T = 300°
\n" ); document.write( "and P = 20 lb/in.2?
\n" ); document.write( "

Algebra.Com's Answer #92749 by marcsam823(57)\"\" \"About 
You can put this solution on YOUR website!
The two key words in this exercise are \"directly\" and \"inversely\".
\n" ); document.write( "--If one variable varies directly with another it increases or decreases as the other increases or decreases. (move in the same direction)
\n" ); document.write( "--If one variable varies inversely as another it decreases as the other increases and increases as the other decreases. (move in opposite directions)\r
\n" ); document.write( "\n" ); document.write( "To translate this algebraically:
\n" ); document.write( "A. \"Volume V varies directly as the Temperature T\" = \"V%2FT\" or divide
\n" ); document.write( "B. \"Volume V varies inversely as the Pressure P\" = \"V%2AP\" or multiply\r
\n" ); document.write( "\n" ); document.write( "Putting this all together:
\n" ); document.write( "\"P%2AV%2FT\"\r
\n" ); document.write( "\n" ); document.write( "1. Table of values
\n" ); document.write( "Let V1 = 465
\n" ); document.write( "Let P1 = 10
\n" ); document.write( "Let T1 = 310\r
\n" ); document.write( "\n" ); document.write( "Let P2 = 20
\n" ); document.write( "Let T2 = 300
\n" ); document.write( "2. Find V2\r
\n" ); document.write( "\n" ); document.write( "3.\"P%2AV%2FT+=+P1%2AV1%2FT1+=+P2%2AV2%2FT2\" Set up a proportion:
\n" ); document.write( "4.\"P%2AV%2FT+=+10%2A465%2F310+=+20%2AV2%2F300\" Substitute the given values
\n" ); document.write( "5.\"P%2AV%2FT+=+15+=+20%2AV2%2F300\" Solve for V2
\n" ); document.write( "6.\"4500+=+20%2AV2\" Cross-multiply
\n" ); document.write( "7.\"V2+=+225\"
\n" ); document.write( "8. Check your answer
\n" ); document.write( "\"10%2A465%2F310+=+15\"
\n" ); document.write( "\"20%2A225%2F300+=+15\"
\n" ); document.write( "\"15+=+15\"
\n" ); document.write( "The answer is correct.
\n" ); document.write( "
\n" );