document.write( "Question 126593: Two trains leave a city at the same time. One travels north, and the other travels south 20 mph faster. In 2hr, the trains are 280 mi apart, find their speeds. \n" ); document.write( "
Algebra.Com's Answer #92740 by marcsam823(57)\"\" \"About 
You can put this solution on YOUR website!
For this problem you'll need to remember that rate x time = distance or \"r%2At+=+d\"
\n" ); document.write( "We know that both trains travelled a distance that separated them by 280 miles after 2 hours. Therefore:\r
\n" ); document.write( "\n" ); document.write( "--The distance travelled by the northbound train (x) plus the distance travelled by the southbound train (y) totals 280 miles or, algebraically:
\n" ); document.write( "\"x+%2B+y+=+280\"\r
\n" ); document.write( "\n" ); document.write( "1. Using our formula \"r%2At+=+d\" we can substitute:
\n" ); document.write( "a. Let r = the speed of the northbound train
\n" ); document.write( "b. Let \"r+%2B+20\" = the speed of the southbound train (20 mph faster)
\n" ); document.write( "c. Both trains have travelled for 2 hours:
\n" ); document.write( "d. Let x = \"2%2Ar\"
\n" ); document.write( "e. Let y = \"2%2A%28r+%2B+20%29\" \r
\n" ); document.write( "\n" ); document.write( "2. Substitute for x and y and solve for r:
\n" ); document.write( "\"2r+%2B+2%28r%2B20%29+=+280\"
\n" ); document.write( "\"2r+%2B+2r+%2B+40+=+280\"
\n" ); document.write( "\"4r+=+240\"
\n" ); document.write( "\"r+=+60\"
\n" ); document.write( "\"r+%2B+20+=+80\"
\n" ); document.write( "-The northbound train travels at 60 mph
\n" ); document.write( "-The southbound train travels at 80 mph (20 mph faster)\r
\n" ); document.write( "\n" ); document.write( "3. Check:
\n" ); document.write( "\"2r+%2B+2%28r+%2B+20%29+=+280\"
\n" ); document.write( "\"2%2860%29+%2B+2%28%2860%29+%2B+20%29+=+280\"
\n" ); document.write( "\"120+%2B+2%2880%29+=+280\"
\n" ); document.write( "\"120+%2B+160+=+280\"
\n" ); document.write( "\"280+=+280\"
\n" ); document.write( "
\n" );